If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-5x-11=3
We move all terms to the left:
x^2-5x-11-(3)=0
We add all the numbers together, and all the variables
x^2-5x-14=0
a = 1; b = -5; c = -14;
Δ = b2-4ac
Δ = -52-4·1·(-14)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-9}{2*1}=\frac{-4}{2} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+9}{2*1}=\frac{14}{2} =7 $
| -6h-4=32+6h | | 231=79-y | | 5x+12+x+x=180 | | B-1=-13+4b | | x^2-5x-11=13 | | -57-s=88 | | -6o-10=-19-3o | | 4(3+x)-x=6+3(x-2 | | (w-17)/9=2 | | -6o-10=-19-30 | | 25-4x=-35 | | -3j-3=-39+3j | | 5x(7-5)=50 | | 3y−1=2 | | Y=0.4x+10 | | 3j-3=-39+3j | | 9=c+13 | | |x|-7=-3 | | -15.7d+8.29=3.39-16.4d | | ∠A=10x+24∘ | | (5x-22)=(3x+10) | | -2s+6=-18+s | | 16x-33=14x-24 | | 2i+8=5i+2 | | 1=h+19 | | 2g−3=3 | | 16.7z=-11.16+16.1z | | 45=0.4x+10 | | -1/5(x-5)-9=7 | | 60.50x+.20=192.10 | | .20x+60.50=192.10 | | 17=23-q |